Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100 and a standard deviation sigma equals 20. Find the probability that a randomly selected adult has an IQ less than 132. The probability that a randomly selected adult has an IQ less than 132 is?
Accepted Solution
A:
Step-by-step explanation:First find the z-score.z = (x - μ) / σz = (132 - 100) / 20z = 1.6From a z-score table:P(z<1.6) = 0.9452So there's a 94.52% probability that a randomly selected adult will have an IQ less than 132.